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| 1. |
A 1.0 m long metallic rod is rotated with an angular frequency of 400 rad s^(-1) about an axis normal to the rod passing through its one end. The other end of the rod is in contact with a circular metallic ring. A constant and uniform magnetic field of 0.5 T parallel to the axis exists everywhere. Calculate the emf developed between the centre and the ring. |
| Answer» Solution :`varepsilon=(BLV)/(2)=(BL^(2).OMEGA)/(2) [because v=lomega]=(0.5xx1xx1xx400)/(2)=100V` | |