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A `1.5 mu F` capacitor is charged of 60 V. The charging battery is then disconnected and a 15 mH coil is connected in series with the capacitor so that LC oscillations occur. Assuming that the circuit contains no resistance, the maximum current in this coil shall be close toA. `1.4 A`B. ` 1.2 A`C. `0.8 A`D. `0.6 A` |
Answer» Correct Answer - D Here `q_(0)=CV=1.5xx10^(-6)xx60=9xx10^(-5)C` Oscillating charge in LC circuit, `q=q_(0)sin (omega t+(pi)/(2))` `therefore` Oscillating current, `I=(dq)/(dt)=q_(0)omega cos(omega t+(pi)/(2))` `thereofre` Maximum current, `I_(0)=q_(0)omega=(q_(0))/(sqrt(LC))" "(because omega = (1)/(sqrt(LC)))` `=(9xx10^(-5))/(sqrt(15xx10^(-3)xx1.5xx10^(-6)))=0.6 A` |
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