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A_(1) & A_(2) are two ores of metal M. Ar on calcination gives black precipitate, CO_(2)& water. |
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Answer» SOLUTION :`CuCO_(3), CU(OH)_(2), Cu_(2)S, Cu, CUO, Cu_(2)l_(2), SO_(2)` `A_(1) = Cu(OH)_(2), CuCO_(3)` `A_(2)= Cu_(2)S` `Cu(OH)_(2) CuCO_(3)OVERSET(cabination)to 2CuO+CO_(2)+overset(H_(2)O)(Black 0Solid)` `Cu(OH)_(2)CuCO_(3)overset(dillHCl)toCUCl_(2)+CO_(2)+3H_(2)O` `2CU_(2)Cl_+4Klto2Cu_(2)I_(2)+I_(2)+4KCI` `underset(A_(2))(2Cu_(2)S)+3O_(2)to2CU_(2)O+2SO_(2)` Cu_(2)S+3O_(2)to6Cu+SO_(2)` |
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