[a+1/b]^m*[a-1/b]^n/[b+1/a]^m*[b-1/a]^n=[a/b]^m+n – InterviewSolution

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1.	[a+1/b]^m[a-1/b]^n/[b+1/a]^m[b-1/a]^n=[a/b]^m+n
Answer» [a+1/b]^m[a-1/b]^n/[b+1/a]^m[b-1/a]^n=[a/b]^m+n

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