1.

A_(1)g of an element gives A_(2)g of its oxide. The equivalent mass of the element is:

Answer»

`(A^(2)-A_(1))/(A_(1))XX8`
`(A_(2)-A_(1))/(A_(2))xx8`
`(A_(1))/(A_(2)-A_(1))xx8`
`(A_(2)-A_(1))xx8`

ANSWER :C


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