1.

A 1 M solution of glucose reaches dissociation equilibrium according to equation given below 6HCHO hArrC_(6)H_(12)O_(6). What is the concentration of HCHO at equilibrium of equilibrium constant is 6xx10^(22)

Answer»

`1.6xx10^(-8)M`
`3.2xx10^(-6)M`
`3.2xx10^(-4)M`
`1.6xx10^(-4)M`

Solution :`6HCHO hArrH_(6)H_(12)O_(6)` FORWARD reaction
`C_(6)H_(12)O_(6)overset(K_(1))hArr6HCHO` backward reaction
`K_(2)=[(1)/(K_(1))]^(1//6),K_(2)=[(1)/(6xx10^(22))]^(1//6)`
`K_(2)=1.6xx10^(-4)M`


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