1.

A `1 mu A` beam of protons with a cross - sectional area of `0.5 sq.mm` is moving with a velocity of `3 xx 10^(4) ms^(-1)` . Then charge density of beam isA. `6.6 xx 10^(-4) C//m^(3)`B. `6.6 xx 10^(-5) C//m^(3)`C. `6.6 xx 10^(-6) C//m^(3)`D. None of these

Answer» Correct Answer - B
For one second , distance = velocity = `3 xx 10^(4) m//sec` and `Q = i xx 1 = 10^(-6) C`.
`"Charge density" = (" charge )/(Volume")`
` = (10^(-6))/( 3 xx 10^(4) xx 0.5 xx 10^(-6))`
`= 6.6 xx 10^(-5) C//m^(3)`.


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