1.

A 10 g mixture of Cu_(2)S and CuS was treated with 200 ml of 0.75 M KMnO_(4) in acid solution producing SO_(2),Cu^(2+) and Mn^(2+). The SO_(2) was boiled off and the excess of KMnO_(3) was treated with 175 ml of 1 M Fe^(2+) solution. Calculate % of CuS in the mixture.

Answer»


ANSWER :`0.0058`


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