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(a) 10 g of non-electrolyte solute dissolved in 50 g of benzene lowered the freexing point of benzene by 0.4 K. Find the molar mass of the solute.[Given : Freezing point depression constant of benzene = 5.12 K. kg mor^(-1)] (b) How solubility of a gas in liquid varies with (i) Temperature and (ii) pressure? |
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Answer» Solution :(a) `M_2 = (k_f xx w_2 xx 1000)/(DELTA T_f xx w_1)` `M_2 = (5.12 k KG mol^(-1) xx 1.0 g xx 1000 g kg^(-1))/(0.4 xx 50 g)` `M_2 = 256 g mol^(-1)`. (B)(i) Solubility decreases with increases in temperature. OR Solubility increases with DECREASE in temperature. OR Solubility varies INVERSELY with temperature. (ii) Solubility increases with increases in pressure. OR Solubility decreases with decrease in pressure. OR Solubility varies directly in pressure OR Solubility varies directly with pressure. |
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