1.

A 10 mu F capacitor is in series with a 50 Omega resistance and the combination is connected to a 220 V, 50 Hz line. Calculate (i) the capacitivereactance, (ii) the impedance of the circuit and (iii) the current in the circuit.

Answer»

Solution :Here, `C = 10 mu F = 10 xx 10^(-6) = 10^(-5)F`
(i) Capacitive reactance,
`X_(C) = (1)/(omega C) = (1)/(2pi v C) = (1)/(2 xx 3.14 xx 50 xx 10^(-5)) = 318.5 Omega`
(ii) Impedance of CR CIRCUIT.
`Z_(CR) = sqrt(R^(2) + X_(C)^(2)) = sqrt((50)^(2) + (318.5)^(2))`
`= 322.4 Omega`
(III) Current, `I_(rms) = (E_(rms))/(Z_(CR)) = (220)/(322.4) = 0.68 A`


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