A 10 V cell of negligible internal resistance is connected in parallelacross a battery of emf 200 V and internal resistance 38 Omegaas shownin the Fig. Find the value of current in the circuit.

A 10 V cell of negligible internal resistance is connected in parallel

1.	A 10 V cell of negligible internal resistance is connected in parallelacross a battery of emf 200 V and internal resistance 38 Omegaas shownin the Fig. Find the value of current in the circuit.
Answer» Solution :Net VOLTAGE in the circuit V= (200 – 10) V= 190 V and net resistance `R = 38 Omega` ` therefore ` VALUE of CURRENT in the circuit `I= V/R = 190/38 = 5A`

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A 10 V cell of negligible internal resistance is connected in parallelacross a battery of emf 200 V and internal resistance 38 Omegaas shownin the Fig. Find the value of current in the circuit.

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