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A 10 wire potentiometer has a resistance of 10` Omega` and is connected to fan accumulator of 2 V and negligible internal resistance.There are two resistance boxes `R_(1)` and `R_(2)` in series with the accumulator and one can have any intergral values of resistance from resistance boxes . A standard-cell of 1.018 V with a sensitive galvanometer in series with it is connected across `R_(1)`.How would you proceed with the above arrangement to obtain potential drop of 1 `mu` V per mm of the potentiometer wire? Calculate the vlue3s of `R_(1)` and `R_(2)` requried. What length of this potentiometer will balance the thermo emf of and copper couple at `300^(@)C` which develops 17`muV//^(0)C?`

Answer» Correct Answer - Put `R_(1)` =1018 `Omega`(1000 times emf of Cd-cell),adust `R_(2)` till no deflection ocurs in the galvanometer , `R_(2)`=972 `Omega`;5.1 m


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