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A `100 km` telegraph wire hasd capacity of `0.02 mu F//km`, if it carries an alternating current of frequency `5 kHZ`. The value of an inductrance required to be connected in series so that the impedance is minimum.A. `50.7 mH`B. `5.07 mH`C. `0.507 mH`D. `507 mH` |
Answer» Correct Answer - 3 `omega = (1)/(sqrt(LC)) implies L = (1)/(omega^(2)C) = (1)/((2 pi n)^(2) C)` |
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