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A 100 mH inductor, a 20 mu F capacitor and a 10 Omega resistor are connected in series to a 100 V a.c. source. Calculate (i) impedance of circuit at resonance (ii) current at resonance (iii) resonant frequency. |
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Answer» Solution :(i) IMPEDANCE of CIRCUIT at resonance `Z = R = 10 Omega` (ii) Current at resonance `= (E)/(R) = (100)/(10) = 10 A` (III) Resonant frequency, `v_(0) = (1)/(2pi sqrt(LC))` `v_(0) = (1)/(pisqrt((100 xx 10^(-3))(20 xx 10^(-6)))) = 112.5 Hz` |
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