1.

A 100 millihenray coil carries a current of 1A. Energy stored in its magnetic field is

Answer»

0.5 J
1 J
0.05 J
0.1 J

Solution :Energy STORED `E=(1)/(2)LI^(2)=(1)/(2)xx(100xx10^(-3))xx1^(2)=0.05 J`


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