1.

A 100 mL solution of 0.1 N HCI was titrated with 0.2 N NaOH solution. The titration was discontinued after adding NaOH solution.The remaining titration was completed by adding 0.25 N KOH solution. The volume of KOH required for completing the titration is

Answer»

70 mL
32 mL
35 mL
16 mL

Solution :`N_(1)V_(1) = N_(2)V_(2) + N_(3)V_(3)`
i.e. `0.1 xx 100 = 0.2 xx 30 + 0.25 V_(3)`
`0.25 V_(3) =4` or `V_(3) = 16 mL`


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