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A 100 ml solution of 0.1 N HCl was titrated with 0.2 N NaOH solution. The titration was discontinued after adding 30 ml of NaOH solution. The remaining titration was completed by adding 0.25 N KOH solution. The volume of KOH required for completing the titration is |
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Answer» 70 ml i.e., `0.1xx100=0.2xx30+0.25V_(3)` `"or"0.25V_(3)=4 or V_(3)=16ml` |
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