1.

A 100 ml solution of 0.1 N HCl was titrated with 0.2 N NaOH solution. The titration was discontinued after adding 30 ml of NaOH solution. The remaining titration was completed by adding 0.25 N KOH solution. The volume of KOH required for completing the titration is

Answer»

70 ml
32 ml
35 ml
16 ml

Solution :`N_(1)V_(1)=N_(2)V_(2)+N_(3)V_(3)`
i.e., `0.1xx100=0.2xx30+0.25V_(3)`
`"or"0.25V_(3)=4 or V_(3)=16ml`


Discussion

No Comment Found