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A 100 mu F capacitor in series with a 40 Omegaresistance is connected to a 110V. 60 Hz supply. What is the maximum current in the circuit ? |
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Answer» Solution :For a RC CIRCUIT, if `V=V_(0) sin omega t` `I=(V_(0))/(sqrt(R^(2)+(I//omega C)^(2))) sin(omega t+phi)` where `tan phi=(1)/(omegaCR)` (a) `I_(0)=3.23A` (B) `phi=33.5^(@)` Time LAG `=(phi)/(omega)=1.55ms` |
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