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A 100(mu)F capacitor is joined to a 24 V battery through a 1.0 M(Omega) resistor.Plot qualitative graphs (a) between current and time for the first 10 minutes and (b)between charge and time for the same period . |
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Answer» SOLUTION :Time constant = rC ` = 1 XX (10^6) xx 100 xx (10^-6) ` ` 100 sec. ` ` (a) q = VC (1-e^(-t/rc))` ` I = Current = dq/dt ` ` = VC/rC .e^(-t/RC)` ` = V/re^(-t/RC)` ` = 24 xx (10^-6). E^(1/(t/100))` ` t = 10 MIN = 600 sec. ` ` q = 24 xx (10^-4) xx (1- (e^-6))` ` = 23.99 xx (10^-4) ` ` i = 24/(10^6) i/e = 5.9 xx (10^-8) amp. ` ` (b) q = VC.(1-e^(-t/rc)). |
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