1.

A `100 Omega` resistance and a capacitor of `100 Omega` reactance are connected in series across a `220` V source. When the capacitor is `50%` charged, the peak value of the displacement current isA. 2.2 AB. 0.45833333333333C. 4.4 AD. `11sqrt(2)` A

Answer» Correct Answer - A
Impedance of the R-C circuit, `Z= sqrt(R^(2)+X_(C)^(2))`
Where, `R=100Omega` and `X_(C) = 100Omega`
`rArr Z=sqrt((100)^(2)+(100)^(2))` = `100sqrt(2)Omega`
Peak value of the current,
`I_("max") = V_("max")/Z = (220sqrt(2))/(100sqrt(2))`=2.2 A


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