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A `100 Omega` resistance and a capacitor of `100 Omega` reactance are connected in series across a `220` V source. When the capacitor is `50%` charged, the peak value of the displacement current isA. 2.2 AB. `11A`C. 4.4 AD. 11`sqrt(2)A` |
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Answer» Correct Answer - A `X_(C)=100` `R=100` `Z=sqrt((100)^(2)+(100)^(2))=100sqrt(2)` `I=(E)/(Z)=(220)/(100sqrt(2))=(2.2)/(sqrt(2))` `I_(0)=sqrt(2)I=(2.2)/(sqrt(2))xxsqrt(2)=2.2A` |
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