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A 100 Omega resistor is connected to a 200V, 50 Hz ac supply. (a) What is the rms value of current in the circuit ? (b) What is the net power consumedover a fully cycle ? |
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Answer» SOLUTION :(a) `I_(rms) = ( V_(rms)) /( |Z|)` `= ( V_(rms))/( R ) ( :. ` Here `|Z |= R )` `= ( 220)/( 100)` `= 2.2 A` (b) `P = ( V_(rms)^(2))/ (R )` ( For purely RESISTIVE AC CIRCUIT ) `((220)^(2))/( 100)` `:. P = 484 W` |
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