1.

A 100-watt, 110-volt incandescent lamp is connected in series with an electrolytic cell containing cadmium sulphate solution. What weight of cadmium will be deposited by the current flowing for 10 hours ?

Answer»

Solution :We know
current in amperes `= ("wattage")/("voltage") = (100)/(110)`……….(Eqn. 5)
Further, CHARGE in coulombs = current in amperes `xx` TIME in seconds
`= (100)/(110) xx 10xx 60 xx 60 = 32727.27`
`therefore` charge in faraday `= (32727.27)/(96500)F = 0.34 F`
`therefore` mole of electricity = 0.34 F.
Amount of Cd deposited = 0.34 eq.
`= (0.34 xx eq. wt.)g`
`= 0.34 xx (112.4)/(2) = 19.11 g`
`("eq. wt. of CADMIUM " = (112.4)/(2))`


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