1.

A 100W and 110V incandescent lamp is connected in series with an electrolytic cell containing CdSO_4 solution. What mass of cadmium will be deposited at the cathode after 4hrs of electricity.

Answer»

Solution :Step I:
Calculation of the quantity of charge passed:
We know, that
Watt= Ampere `times` volt
`Ampere= (WAT t)/(Vol t)=100/110`
Now charg e= Current `times` Time
`=(100/110 amp.)times 4 times 60 times 60`
`=13091 C`
Step II:
Calculation of mass of CADMIUM deposited:
The cathodic reaction is
`Cd^(2+) (aq)+2e^(-) to Cd(s)`
`112.2g 2 times 96500 C`
`because 2 times 96500 C` of charge deposited Cd=112.2 g
`THEREFORE 13091C` charge will DEPOSITE Cd
`=(112.2g)/(2 times 96500 C) times 13091C`
=7.61g


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