1.

A 10cm^(3) sample of human urine was found to have 5 milligrams of urea on analysis. Calculate the molarity of given sample with respect to urea (Mol. Mass of urea - 60).

Answer»


Solution :CONCENTRATION of urea = 5 mg in 10 `CM^(3)` = `"500 mg L"^(-1)="0.50 g L"^(-1)="0.5/60 MOL L"^(-1)="0.0083 mol L"^(-1)`


Discussion

No Comment Found