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InterviewSolution
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A 10kw drilling machine is used for 5 minutes to bore a hole in an aluminium block of mass `10xx10^(3)kg`. If 40% of the work done is utilised to raise the temperature of the block, then find the raise in temperature of the aluminium block? (Specific heat of Aluminium `=0.9 Jkg^(-1)k^(-1)`) |
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Answer» Work done by the drilling machine in 5 min W=power x time `=10xx10^(3)xx5xx60=3xx10^(6)J` The energy utilised to rise the temperature of the block `=40% "of" W=3xx10^(6)xx(40)/(100)=12xx10^(5)J` Heat gained by aluminimum block= mass xx specific heat xx increase in temperature `12xx10^(5)=(10xx10^(3))xx0.9xxDeltat` `therefore Deltat=(12xx10^(5))/(0.9xx10^(4))=133.3^(@)C` |
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