1.

A 10L cylinder of nitrogen at 4.0 atm pressure and 27^(@ C develped a leakage. When the leakage was repaired 2.36 atm of nitrogen remained in the cylinder still at 27^(@0C. How many grams of nitrogen escaped ?

Answer»

18.7 G
0.67g
52.6g
10.0g

SOLUTION :Moles of `N_(2)` escaped
`= ( 4 XX 10)/( 0.082 xx 300)- ( 2.36 xx 10)/( 0.082 xx 300)= 0.667`
MASS of `N_(2) = 0.667 xx 28 = 18.7 g `


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