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A 10muF capacitor is charged to a voltage of 600 V Suppose it is discharged through an electrolytic bath containing acidified water. How much hydrogen will be liberated? What energy can be gained by burining this hydrogen? How can it be made consistent with the energy conseryation law ?

Answer»


Solution :The capacitor.s charge is `q=Cdeltavarphi, the accumulated energy is `W_("cap")=(1)/(2)C(Deltavarphi)^(2)=1.8J`. The amount of hydrogen produced is `m=(ACDeltavarphi)/(eN_(A)Z)` the quantity of heat liberated in the process of COMBUSTION is `Q=mlamda=9.1xx10^(-3)J`, which is MUCH less than the energy of the capacitor. Obviously, in the course of the discharge

of the capacition through the ELECTROLYTE part of the energy stored in it will be liberated in the form of heat, with only a small fraction heing spent on the CHEMICAL reaction.


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