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A 10muF capacitor is in series with a 50Omega resistance and the combination is connected to a 220 V, 50 Hz line. Calculate (i) the capacitive reactance, (ii) the impedance of the circuit and (iii) the current in the circuit. |
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Answer» Solution :Here, `C=10muF=10xx10^(-6)=10^(-5)F` `R=50ohm, E_("rms")=220V, v=50Hz`, (i) Capacitive reactance, `X_(C)=(1)/(omegaC)=(1)/(2pivC)=(1)/(2xx3.14xx50xx10^(-5))=318.5Omega` (II) Impedance of CR circuit. `Z_(CR)=sqrt(R^(2)+X_(C)^(2))=sqrt((50)^(2)+(318.5)^(2))=322.4Omega` (iii) Current, `I_("rms")=(E_("rms"))/(Z_(CR))=(220)/(322.4)=0.68A` |
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