1.

A 10Omega resistance, 5mH inductor and 10muF capacitor are joined in series. When a suitable frequency of alternating current source is joined to this combination, the circuit resonates. If the resistance is halved, the resonance frequency ……

Answer»

is HALVED
is doubled
remains unchanged
in quadrupled

Solution :At RESONANCE `omegaL=1/(omegaC)`
`therefore omega=1/sqrt(LC)` , where there is no TERM of resistance so on changing the VALUE of resistance there will no CHANGE of `omega`.


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