A 10sqrt3 kg box has to move up an inclined slope of 60^(@) to the horizontal at a uniform velocity of 5 ms^(-1) If the frictional force retarding the motion is 150N, the minimum force applied parallel to inclined plane to move up is (g=10 ms^(-2))

A 10sqrt3 kg box has to move up an inclined slope of 60^(@) to the hor

1.	A 10sqrt3 kg box has to move up an inclined slope of 60^(@) to the horizontal at a uniform velocity of 5 ms^(-1) If the frictional force retarding the motion is 150N, the minimum force applied parallel to inclined plane to move up is (g=10 ms^(-2))
Answer» `300 XX (2)/(SQRT3) N` `300 xx (sqrt3)/(2) N` `300 N` `150 N` Answer :C

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A 10sqrt3 kg box has to move up an inclined slope of 60^(@) to the horizontal at a uniform velocity of 5 ms^(-1) If the frictional force retarding the motion is 150N, the minimum force applied parallel to inclined plane to move up is (g=10 ms^(-2))

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