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InterviewSolution
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A 15.0 mu Fcapacitor is connected to a 220V, 50Hz source. Find the capacitive reactance and the current (rms and peak) in the circuit. If the frequency is doubled, what happens to the capacitive reactance and the current? |
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Answer» Solution :The capacitive reactance is `X_C = (1)/(2pi v C) = (1)/(2pi (50)(15.0 xx 10^(-6) ) ) = 212 Omega` The rms current is = `I = (V)/(X_C) = 220/212 - 1.04 A` The peak currentis `i_m = sqrt21 = (1.41)(1.04)= 1.47 A` This current OSCILLATES between +1.47A and -1.47 A and is ahead of the VOLTAGE by `pi/2` If the frequency is DOUBLED, the capacitive reactance is HALVED and consequently, the current isdoubled. |
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