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| 1. |
A 150 W lamp emits light of mean wavelength of 5500Å. If the efficiency is 12% , find out the number of photons emitted by the lamp in one second. |
| Answer» <html><body><p></p><a href="https://interviewquestions.tuteehub.com/tag/solution-25781" style="font-weight:bold;" target="_blank" title="Click to know more about SOLUTION">SOLUTION</a> :`{:("<a href="https://interviewquestions.tuteehub.com/tag/number-582134" style="font-weight:bold;" target="_blank" title="Click to know more about NUMBER">NUMBER</a> of photons emitted per second n" = (P lambda)/(<a href="https://interviewquestions.tuteehub.com/tag/hc-1016346" style="font-weight:bold;" target="_blank" title="Click to know more about HC">HC</a>),,P = 150 W),(,,lambda 5500Å),("If the efficiency is 12%," eta = (12)/(100) = 0.12,,h = 6.6 <a href="https://interviewquestions.tuteehub.com/tag/xx-747671" style="font-weight:bold;" target="_blank" title="Click to know more about XX">XX</a> <a href="https://interviewquestions.tuteehub.com/tag/10-261113" style="font-weight:bold;" target="_blank" title="Click to know more about 10">10</a>^(-34)Js),(n = (P eta lambda)/(hc),,c = 3 xx 10^(8) ms^(-1)):}` <br/> `= (150 xx 0.12 xx 5500 xx 10^(-10))/(6.6 xx 10^(34) xx 3 xx 10^(8)) = (99000 xx 10^(-10))/(19.8 xx 10^(-26)) = 5000 xx 10^(16)` <br/> `n = 5 xx 10^(19)`</body></html> | |