InterviewSolution
Saved Bookmarks
| 1. |
A `1kg` stone at the end of `1m` long string is whirled in a vertical circle at a constant speed of `4m//s`. The tension in the string is `6N`, when the stone is at `(g=10m//s^(2))`A. top of the circleB. bottom of the circleC. half way downD. non of the above |
|
Answer» Correct Answer - A `mg=1xx10=10N,(mv^(2))/(r)=(1xx(4)^(2))/(1)=16` Tension at the top of circle `=mv^(2)/(r)=mg=6N` Tension at the bottom of circle `(mv^(2))/(r)+mg=26N` |
|