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A 1kW heater is meant to operate at 200 V. (a) What is its resistance ? (b) How much power will it consume if the line voltage drops to 100 V ? (c ) How many units of electrical energy will it consume in a month (of 30 days) if it operates 10 hr daily at the specified voltage? |
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Answer» <P> Solution :a) The resistance of an electric APPLIANCE is GIVEN by,`R=(V_(S)^(2))/(W)"so,"R=((200)^(2))/(1000)=40Omega` b) The .actual power. consumed by an electric appliance is given by, `P=((V_(A))/(V_(S)))^(2)XXW"so,"P=((100)/(200))^(2)xx1000=250W` c) The total ELECTRICAL energy consumed by an electric appliance in a specified time is given by, `E=(SigmaW_(1)h_(1))/(1000)kWh` `"So, "E=(1000xx(10xx30))/(1000)=300kWh` |
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