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(A) 2/3 sec(B) 1/6 sec(C) 1/2 secThe kinetic energy K of a particle movingalong a cirde of radius R depends on the distance covered sa is a positive constant. The total force acting on the particle isAU (Eng. 1w7 11/2R2 |
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Answer» Given K.E = 1/2 mv² = as² = mv² = 2as² now differenciating with respect to t 2mv = dv/dt = 4as ds/dt = 4asv mat = 2 as Hence Ft = 2 as here (Ft = tangential force) ..... 1> centripetal force = Fc = mac = mv²/R = 2 mas²/ mR = 2as²/R ..... 2> now net force of particle is =√Ft² + F² c =√(2as)² + (2as²/R)² = 2 as(√1 + s²/R² or 2as(1 + s²/R²) raise to power 1/2 |
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