A^2+b^2+3^2+2ab+2bc+2ac equals to plzzz answer

1.	A^2+b^2+3^2+2ab+2bc+2ac equals to plzzz answer
Answer» Answer: Step-by-step explanation: So, here we go: a2+b2+c2−2ab−2bc−2ca+3ABC =a2−2ab+b2+c2−2bc−2ca+3abc [using the identiy (a−b)2=a2−2ab+b2) ] =(a−b)2+c2−2c(b+a)+3abc =(a−b)2+c[c−c(b+a)+3ab] Now we have the most SIMPLIFIED polynomial which is equal to the polynomial given in the question. Hence, substituting values in this polynomial will GIVE the same result as it would have been in substituting values in the given polynomial. So, here we go: =(a−b)2+c[c−c(b+a)+3ab] =(2−3)2+(−2)[(−2)−2(3+2)+3(2)(3)] =(−1)2−2[(−2)−2(5)+18] =1−2(−2−10+18) =1−2(6) =1−12 =−11 Therefore, the value of a2+b2+c2−2ab−2bc−2ca+3abc is -11

Answer»

Answer:

Step-by-step explanation:

So, here we go:

a2+b2+c2−2ab−2bc−2ca+3ABC

=a2−2ab+b2+c2−2bc−2ca+3abc

[using the identiy (a−b)2=a2−2ab+b2) ]

=(a−b)2+c2−2c(b+a)+3abc

=(a−b)2+c[c−c(b+a)+3ab]

Now we have the most SIMPLIFIED polynomial which is equal to the polynomial given in the question.

Hence, substituting values in this polynomial will GIVE the same result as it would have been in substituting values in the given polynomial.

So, here we go:

=(a−b)2+c[c−c(b+a)+3ab]

=(2−3)2+(−2)[(−2)−2(3+2)+3(2)(3)]

=(−1)2−2[(−2)−2(5)+18]

=1−2(−2−10+18)

=1−2(6)

=1−12

=−11

Therefore, the value of a2+b2+c2−2ab−2bc−2ca+3abc is -11

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