A 2 kg weight is attached to the lower end of a spring which is hanging vertically producing in it an elongation of 4xx10^(-2)m. Then potential energy of the stretched spring is

A 2 kg weight is attached to the lower end of a spring which is hangin

1.	A 2 kg weight is attached to the lower end of a spring which is hanging vertically producing in it an elongation of 4xx10^(-2)m. Then potential energy of the stretched spring is
Answer» 0.392 J 3.92 J 39.2 J 392 J SOLUTION :`PE=(1)/(2)Fl` `=(1)/(2) XX 2 xx 9.8 xx 4 xx 10^(-2) = 39.2 xx10^(-2)` `=0.392J.`

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A 2 kg weight is attached to the lower end of a spring which is hanging vertically producing in it an elongation of 4xx10^(-2)m. Then potential energy of the stretched spring is

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