1.

A 20.0 mL mixture of CO,CH_(4)and He gases is exploded by an electric discharge at room temperature with excess of oxygen. The volume contraction is found to be 13.0 cm^(3) . A further contraction of 14.0 cm^(3)occurs when the residual gas is treated with KOH solution. Find out the composition of the gaseous mixture in terms of volume percentage.

Answer»

Solution :`CO(G) + 1/2 O_(2)(g) rarr CO_(2)(g)`
`CH_(4)(g) + 2O_(2)(g) rarr CO_(2)(g) + 2H_(2)O(L)`
'X' is the VOLUME of CO and y is+ the volume of `CH_(4)`
Thus, 1/2 x + y = 13........ (i)
x + y =14........ (ii)
By solving eq. (i) & (ii), we get
x = 2 cc , y = 12 cc
Thus, % `CH_(4) = 60 , % CO = 10 , % He = 30 `


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