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A 20.0 mL mixture of CO,CH_(4)and He gases is exploded by an electric discharge at room temperature with excess of oxygen. The volume contraction is found to be 13.0 cm^(3) . A further contraction of 14.0 cm^(3)occurs when the residual gas is treated with KOH solution. Find out the composition of the gaseous mixture in terms of volume percentage. |
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Answer» Solution :`CO(G) + 1/2 O_(2)(g) rarr CO_(2)(g)` `CH_(4)(g) + 2O_(2)(g) rarr CO_(2)(g) + 2H_(2)O(L)` 'X' is the VOLUME of CO and y is+ the volume of `CH_(4)` Thus, 1/2 x + y = 13........ (i) x + y =14........ (ii) By solving eq. (i) & (ii), we get x = 2 cc , y = 12 cc Thus, % `CH_(4) = 60 , % CO = 10 , % He = 30 ` |
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