1.

A 20 a.m.u. atom emits photon of 6.6Å while making a transition from excited state to ground state. The recoil energy of the atom will be :

Answer»

<P>`1.5xx10^(-23)J`
`3.5xx10^(-23)J`
`5.1xx10^(-23)J`
`7.5xx10^(-23)J`

Solution :`:.p=(H)/(LAMBDA)`


Discussion

No Comment Found

Related InterviewSolutions