A 20 g bullet travelling with a velocity v becomes embedded into a 4 kg block of wood suspended from two light strings. If the block-bullet combination rises to a height of 2 m, what is the initial velocity v of the bullet ?I will Mark you briliantist ! Good Evening !!!....xD or sab kase ho ??bhul gaya kya mujha ¿¿

A 20 g bullet travelling with a velocity v becomes embedded into a 4 k

1.	A 20 g bullet travelling with a velocity v becomes embedded into a 4 kg block of wood suspended from two light strings. If the block-bullet combination rises to a height of 2 m, what is the initial velocity v of the bullet ?I will Mark you briliantist ! Good Evening !!!....xD or sab kase ho ??bhul gaya kya mujha ¿¿
Answer» The situation is as shown in the figure.Let V be velocity of the BLOCK-bullet system just after COLLISION. Then by the LAW of conservation of linear momentum, we getmv=(m+M)VV= m+Mmv Let the block rises to a height h.According to law of conservation of mechanical energy,we get21 (m+M)V 2 =(m+M)ghh= 2gV 2 = 2gv 2 ( m+Mm ) 2 .Step-by-step explanation:Fever KAISA hai abb?