1.

A 20 gm mixture of Ca(OH)_(2) and CaCl_(2) require 50ml 2M HCl for complete reaction Then what will be the mass % of Ca(OH)_(2)

Answer»

0.037
0.185
0.37
0.0925

Solution :`n_(Cal(OH)_(2))=a n_(CaCl_(2))=B`
`74a+111b=20`. . . .(i)
`Ca(OH)_(2)+2HClrarrCaCl_(2)+2H_(2)O`
`n_(Ca(OH)_(2))=a=(n_(HCL))/(2)=(50xx2)/(1000xx2)=(1)/(20)=(0.1)/(2)`
`W_(Ca(OH)_(2))=(7.4)/(2)gm=3.7`
MASS `% Ca(OH)_(2))=(3.7)/(20)xx100=18.5%`


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