A 20 litre box contains O3 and O2 in equilibrium at 500K. Kp=4×1014 a

1.	A 20 litre box contains O3 and O2 in equilibrium at 500K. Kp=4×1014 atm for 2O3(g)⇌3O2(g). Assume that pO2>>pO3 and if the total pressure is 8 atm and the moles of O3 at equilibrium are x×10−7, x will be (Take √5=2.2, √3=1.7, √2=1.4, R= 0.08 atm L mol−1 K−1)
Answer» A 20 litre box contains $O_{3}$ and $O_{2}$ in equilibrium at 500K. $K_{p} = 4 \times 10^{14}$ atm for $2 O_{3} (g) ⇌ 3 O_{2} (g)$ . Assume that $p_{O_{2}} >> p_{O_{3}}$ and if the total pressure is 8 atm and the moles of $O_{3}$ at equilibrium are $x \times 10^{- 7}$ , x will be (Take $\sqrt{5} = 2.2$ , $\sqrt{3} = 1.7$ , $\sqrt{2} = 1.4$ , R= 0.08 $a t m L m o l^{- 1} K^{- 1}$ )

A 20 litre box contains O3 and O2 in equilibrium at 500K. Kp=4×1014 atm for 2O3(g)⇌3O2(g). Assume that pO2>>pO3 and if the total pressure is 8 atm and the moles of O3 at equilibrium are x×10−7, x will be (Take √5=2.2, √3=1.7, √2=1.4, R= 0.08 atm L mol−1 K−1)

Answer»

A 20 litre box contains $O_{3}$ and $O_{2}$ in equilibrium at 500K. $K_{p} = 4 \times 10^{14}$ atm for $2 O_{3} (g) ⇌ 3 O_{2} (g)$ . Assume that $p_{O_{2}} >> p_{O_{3}}$ and if the total pressure is 8 atm and the moles of $O_{3}$ at equilibrium are $x \times 10^{- 7}$ , x will be

(Take $\sqrt{5} = 2.2$ , $\sqrt{3} = 1.7$ , $\sqrt{2} = 1.4$ , R= 0.08 $a t m L m o l^{- 1} K^{- 1}$ )

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A 20 litre box contains O3 and O2 in equilibrium at 500K. Kp=4×1014 atm for 2O3(g)⇌3O2(g). Assume that pO2&gt;&gt;pO3 and if the total pressure is 8 atm and the moles of O3 at equilibrium are x×10−7, x will be (Take √5=2.2, √3=1.7, √2=1.4, R= 0.08 atm L mol−1 K−1)

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A 20 litre box contains O3 and O2 in equilibrium at 500K. Kp=4×1014 atm for 2O3(g)⇌3O2(g). Assume that pO2>>pO3 and if the total pressure is 8 atm and the moles of O3 at equilibrium are x×10−7, x will be (Take √5=2.2, √3=1.7, √2=1.4, R= 0.08 atm L mol−1 K−1)