A 20 mL mixture of ethane, ethylene, and `CO_2` is heated with `O_2`. After the explosion, there was a contraction of 28 mL and after treatment with KOH, there was a further contraction of 30 mL. What is the composition of the mixture?

A 20 mL mixture of ethane, ethylene, and `CO_2` is heated with `O_2`.

1.	A 20 mL mixture of ethane, ethylene, and `CO_2` is heated with `O_2`. After the explosion, there was a contraction of 28 mL and after treatment with KOH, there was a further contraction of 30 mL. What is the composition of the mixture?
Answer» Let the volume of ethane, ethylene, and `CO_(2)`, respectively, are a,b and `(20-a-b)mL` Now contraction after cooling`=28mL` `thereforeV_(R)-V_(P)=25` `V_(R)=` Volume of `C_(2)H_(6)+` volume of `C_(2)H_(4)+` volume of `CO_(2)+` volume of `O_(2)` used for combustion `V_(P)=` volume of `CO_(2)` produced (Volume of `H_(2)O` is not taken since it condenses) Considering the combustion gases. (a). `C_(2)H_(6)+(7)/(2)O_(2)to2CO_(2)+3H_(2)O` (b). `C_(2)H_(4)+3O_(2)to2CO_(2)+2H_(2)O` (c). `CO_(2)to` no reaction `V_(R)=(a+(7)/(2)a)+(b+3b)+(20-a-b)` `V_(P)=(2a+2b)+(20-a-b)` `V_(P)-V_(R)=(5)/(2)a+2b=28` `therefore5a+4b=56` ..(i) There is a further contraction of 32 mL on treatment with KOH. Volume of `CO_(2)` produced `+` Volume of `CO_(2)` original `=32` `(2a+2b)+(20-a-b)=32` `therefore a+b=12` ...(ii) On solving (i) and (ii) we get `a=8mL` (volume of `C_(2)H_(6))` `b=4mL` (Volume of `C_(2)H_(4))` Volume of `CO_(2)=8mL`

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A 20 mL mixture of ethane, ethylene, and `CO_2` is heated with `O_2`. After the explosion, there was a contraction of 28 mL and after treatment with KOH, there was a further contraction of 30 mL. What is the composition of the mixture?

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