1.

a 200km long train with velocity of 10m/s find the equation of motion of train and time to cross the tunel of 100m​

Answer»

-step explanation:Lwt us consider the front END of TRAIN, So for train to CROSS the tunnel,total DISTANCE = length of train + length of tunnelDistance=200+100=300mvelocity= timedistance ⇒V= 50300 ⇒6m/s



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