1.

A 220 V, 50 Hz a.c. source is connected an inductance of 0.2 H and a resistance of 20 Omegain series. What is the current in the circuit ?

Answer»

`10A`
`5A`
`33.3A`
`3.33A`

SOLUTION :`|Z|=sqrt(R^2+OMEGA^2L^2)`
`=sqrt(400+2500xx0.04)`
`I=V/"|Z|"`
`=sqrt(400+100)`
`=220/22.36`
`=sqrt500`
`THEREFORE` I=9.84 A `APPROX` 10.0 A
`therefore |Z|=22.36 Omega`


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