1.

a) 24 g of a non-volatile, non-electrolyte solute is added to 600 g of water. The boiling point of the resulting solution is 373.35K. Calculate the molar mass of the solute ("Given boiling point of pure water = 373 K and Kb for water=0.52 K kg mol"^(-1)).

Answer»

SOLUTION :GIVEN
`w_(2)=24g`
`w_(1)=600g`
`DeltaT_(B)=0.35 K`
`m_(2)=?`
`"Molar mass of the SOLUTE, "M_(2)=(1000KbW_(2))/(DeltaTbxxw_(1))`
`therefore M_(2)="59.42g mol"^(-1)`


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