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A 250-turns recantagular coil of length 2.1 cm and width 1.25 cm carries a current of `85 muA` and subjected to magnetic field of strength `0.85 T`. Work done for rotating the coil by `180^(@)` against the torque isA. `9.1 mu J`B. ` 4.55 mu J`C. `2.3 muJ`D. `1.15 muJ` |
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Answer» Correct Answer - A `W=MB(cos theta_(1)- cos theta_(2))` When it is rotated by angle `180^(@)` then W=2MB W =2(NIA) B `=2xx250xx85xx10^(-6)[1.25xx2.1xx10^(-4)]xx85xx10^(-2)` `=9.1 muJ` |
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