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A 280 days old radioactive substance showe an activity of 6000 dps. 140 days later its acitivity becomes 3000 dps. What was its initial acitivity? |
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Answer» 2000 dps `N/N_(0)=(1/2)^(3) rArr (3000)/(N_(0))=1/8, N_(0)=24000` |
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