(a^2b^3c)^4 (abc)^3÷(a^3bc^-1)^2=√a^mb^nc^p then m+n+p=? – InterviewSolution

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1.	(a^2b^3c)^4 (abc)^3÷(a^3bc^-1)^2=√a^mb^nc^p then m+n+p=?
Answer» (a^2b^3c)^4 (abc)^3÷(a^3bc^-1)^2=√a^mb^nc^p then m+n+p=?

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